リスト理論の基礎
リストノードの定義
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
203. リストから要素を削除する
class Solution:
def removeElements(self, head, val):
dummy_head = ListNode(next=head)
current = dummy_head
while current.next is not None:
if current.next.val == val:
current.next = current.next.next
else:
current = current.next
return dummy_head.next
707. リストの設計
class LinkedListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
class MyLinkedList:
def __init__(self):
self.dummy_head = LinkedListNode()
self.size = 0
def get(self, index):
if index < 0 or index >= self.size:
return -1
current = self.dummy_head.next
for _ in range(index):
current = current.next
return current.val
def addAtHead(self, val):
new_node = LinkedListNode(val, self.dummy_head.next)
self.dummy_head.next = new_node
self.size += 1
def addAtTail(self, val):
new_node = LinkedListNode(val)
current = self.dummy_head
while current.next is not None:
current = current.next
current.next = new_node
self.size += 1
def addAtIndex(self, index, val):
if 0 <= index <= self.size:
new_node = LinkedListNode(val)
current = self.dummy_head
for _ in range(index):
current = current.next
new_node.next = current.next
current.next = new_node
self.size += 1
def deleteAtIndex(self, index):
if 0 <= index < self.size:
current = self.dummy_head
for _ in range(index):
current = current.next
current.next = current.next.next
self.size -= 1
206. リストの逆転
双方向ポインタを使用した方法
class Solution:
def reverseList(self, head):
current = head
previous = None
while current:
temp = current.next
current.next = previous
previous = current
current = temp
return previous
再帰を使用した方法
class Solution:
def reverseList(self, head):
return self.reverse(head, None)
def reverse(self, current, previous):
if current:
temp = current.next
current.next = previous
return self.reverse(temp, current)
return previous